The Two triangles are similar only if the corresponding faces or sides are in proportion and the corresponding angles are equal. The triangle proof known as similar if all the angles
are equivalent to each other, that it is enough for two triangles to having two pairs of equivalent angles looks like similar. In **similar triangle**, resultant sides are
relative. Inversely, if all three sides of two triangles are relative, then these triangles are similar.

There are three methods of proving similar triangles,

**AA (angle to angle) similar triangles proof:**

If the 2 angles of any one triangle are equal to 2 angles of another triangle, then the triangles are similar. To show two triangles are similar in the above triangles figure.

∡A≅ ∡d

∡B≅∡E

**Then:** ΔABC~ΔDEC

**SSS similar triangles proof (side-side-side proof):**

If the 3 sets of corresponding faces or sides of 2 triangles are in proportion, then the triangles are similar. To show two triangles are similar in the above triangles figure.

`(AB)/(DE)` =`(AC)/(DF)` =`(BC)/(EF)`

Then: ΔABC~ΔDEC

**SAS similar triangles proof (side-angle-side proof):**

If the angles of one triangle are equal to the corresponding angles of another triangle and the side lengths including these angles are in proportion, then the triangles are similar. To show two triangles are similar in the above triangles figure.

∡A≅ ∡D

`(AB)/(DE)` =`(AC)/(DF)`

Then: ΔABC~ΔDEF

- Let us consider triangle ABC. If D and E are the points of cutting each other of a parallel line to BC with sides AB and AC, correspondingly, then triangle ADE is similar to ABC.
- While triangle ADE is related to ABC, and D on AB, E on AC, and then DE is equal to BC.
- AC and AD are called
**segments**of the same line,. - The lines are BC and DE to be parallel, then triangles ABC and ADE are similar.
- In common, while two triangles having coinciding sides, correspondingly, and then they are similar.
- We can consider the right-angled triangle ABC. If BD is a height moving from the right-angle vertex, then triangles ABC, ABD, and BDC known as similar.
- In proof, any line EF vertical to hypotenuse AC forms triangle AFE similar to ABC. The same would hold if E is lie on the BC.
- Angle BCD known as outer in proof angle of triangle ABC.
- It is equivalent to the sum of both non-adjacent angles ABC and BAC in proof.
- The outer angle in proof is superior than every of the two non-adjacent angles of the triangle.
- The segment of the directly line culminating a triangle vertex and the midpoint of the differing site is known as median.
- Hence the similar triangle is proved.